Question

3x+2y=13
2x+5y=5

Answer 1

x = 5
y = -1

Answer 2

Multiply first eqn by 2 and second by 3 then subtract the resulting second one from the resulting first one.

This will eliminate the x variable and you will get value of y

now put this value of y in the given first eqn and get the value of x

Answer 3

d q kc mkuha,,

Answer 4

\[3x -3y=2,x-3y=-2\]

Answer 5

i nid the ans.

Answer 6

ok ill write it for u..

Answer 7

tnx

Answer 8

im,,waiting

Answer 9

i need a clear solution for my two equation..

Answer 10

given eqns
3x + 2y = 13 ------------ (1)
2x + 5y = 5 ------------ (2)

Multiply (1) by 2 and (2) by 3 to get
6x + 4y = 26 ----------- (3)
6x + 15y = 15 ----------- (4)

Subtracting (3) from (4) we get
6x - 6x + 4y - 15y = 26-15
=> -11y = 11
=> y = 11/-11 = -1 so y = -1

Putting y = -1 in (1), we get
3x + 2(-1) = 13
=> 3x -2 = 13
=> 3x = 13 + 2
=> x = 15/3 = x = 5 so x = 5

Final solution : x = 5 and y = -1

Answer 11

Hope it is clear now.......
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Answer 12

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Answer 13

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Answer 14

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Answer 15

i saw it

Answer 16

what about my 2nd equation?
\[3x-3y=2,,,x-3y=-2\]

Answer 17

hey..

Answer 18

here
3x - 3y = 2 ----- (1)
x - 3y = -2 ----- (2)
subtract (2) from (1)
3x-x -3y -(-3y) = 2-(-2)
2x - 3y + 3y = 2 + 2
2x = 4
x = 4/2 =2 so x =2
Putting x=2 in (1)
3(2) - 3y = 2
=> 6 - 3y = 2
=> - 3y = 2-6
=> y = -4/-3 = 4/3