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fr33 or kwe help me on that integral questions : ill post it to down
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\[\int\limits_{}\sqrt{tanx}*dx\]
well I don't know this, I suck at calculus :(
lol...
\[u=sinx/cosx\] then \[du=\sin2-\cos2x*dr\]
then it will be that \[\int\limits_{}\sqrt{sinx/cosx}*\sin2x-\cos2x*dx\]
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where u got the 2? from the index of the radical?
its 2x not 2 sorr
du=sin2x−cos2x∗dr
yup I am lost :p
:P
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