Mathematics
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OpenStudy (anonymous):
convert r=2sin3(theta) to rectangular form?? please:)
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OpenStudy (anonymous):
haha i hav a test on all this stuff tom..so yeahh
OpenStudy (anonymous):
if z = r(cosθ + isinθ)
z^3 = r^3 (cos3θ + isin3θ)
OpenStudy (anonymous):
or can we multiply r to both sides and get r^2=2rcos3(theta)?..n thn end up with x^2+y^2-6y=0?
OpenStudy (amistre64):
r = 2sin^3(t) right?
OpenStudy (anonymous):
how is sin 3θ equal to 6y?
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OpenStudy (anonymous):
no\[r=2\sin3\Theta\]
OpenStudy (amistre64):
r = 2 sin(3t) then, ok
OpenStudy (anonymous):
i multiplied 2 times 3..u cant do tht huh
OpenStudy (anonymous):
no u cant
OpenStudy (anonymous):
oh..lol..k
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OpenStudy (anonymous):
if z = r(cosθ + isinθ) = x + iy
z^3 = r^3 (cos3θ + isin3θ) = (x^3 - 3xy^2) + i(3x^2 y - y^3)
OpenStudy (anonymous):
thats the eqn?
OpenStudy (anonymous):
no..long way to go
OpenStudy (anonymous):
equate the coefficients
r^3sin3θ = (3x^2 y - y^3)
OpenStudy (anonymous):
r u indian?
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OpenStudy (anonymous):
so sin3θ is (3x^2y - y^3)/r^3
now think back to ur original qstn
we get
r^4 = 2(3x^2y - y^3)
OpenStudy (anonymous):
m indian yes..
OpenStudy (anonymous):
wud r^4 b (x^2+y^2)^2
OpenStudy (anonymous):
yes maam
OpenStudy (anonymous):
wer in south india?
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OpenStudy (anonymous):
i come from the extreme north but i live in the capital
OpenStudy (anonymous):
delhi
OpenStudy (anonymous):
yeah..nd m kashmiri
OpenStudy (anonymous):
oh..cool
OpenStudy (anonymous):
wht grade r u in?
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OpenStudy (anonymous):
10
OpenStudy (anonymous):
ohk...
OpenStudy (anonymous):
so uve done complex nos?
OpenStudy (anonymous):
not rlly..our teacher didint go over those tht well
OpenStudy (anonymous):
ohk...theyre really useful..did u get all those rotations i ws doing?
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OpenStudy (anonymous):
yeah:)
OpenStudy (anonymous):
then u know complex quite well
OpenStudy (anonymous):
wht time is it there?
OpenStudy (anonymous):
haha..well..being asian helps with math
OpenStudy (anonymous):
its 4...der?
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OpenStudy (anonymous):
2 in the morning
OpenStudy (anonymous):
oh wow..ohk..well i shud get back 2 all the othr probs:(
OpenStudy (anonymous):
:(..thanks for the medal..post ur probs..ill help:)
OpenStudy (anonymous):
no problem..thnkss
OpenStudy (anonymous):
ur welcome..keep in touch..