Question

what is the solution for
integration sign (sinx.sec2x) dx

Answer 1

\[\int\limits \frac {sinx}{\cos 2x}dx= \int\limits \frac{sinx}{2\cos^2 x-1}dx\]put cosx=y
-sinxdx=dy
\[\int\limits\frac{-dy}{2y^2-1}\]

Answer 2

iam a big fan of urs fiz u r a great mathematician may God bless u!!!!:D