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OpenStudy (anonymous):
what's the tangent line of (x-1)^2=6(y+2) at point (-5, 4)?
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OpenStudy (anonymous):
first i found the derivative... and got (x-1)/3. is that right?
OpenStudy (anonymous):
find dy/dx at (-5,4) it is -2 so slope is -2 y=-2x+k 4=-2*(-5)+k k=-6 y=-2x-6
OpenStudy (anonymous):
yay! kk thanks
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