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OpenStudy (anonymous):
dy/dx=3x-2 where y=2 when x=-1
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OpenStudy (nikita2):
y = 3/2*x^2 - 2*x + Const. Let's find the const: 2 = 3/2*(-1) - 2*(-1) + Const => Const = 3/2. Final: y(x) = 3/2x^2 - 2x + 3/2
OpenStudy (anonymous):
thak you
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