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how do I solve F(x) = 3(x-2)2(exponent) + 1
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solve for what?
\[F(x)=3(x-2)^2+1\] vertex is (2,1)
range is \[[1,\infty)\]
no real zeros since vertex is above x - axis and this is a parabola facing up. what does the question ask?
IDENTIFY AND GRAPH THE BASE FUNCTION
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