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Mathematics 11 Online
OpenStudy (anonymous):

evaluate the series 1+2+4+8+....+a10

OpenStudy (anonymous):

1(2^9 - 1)/2 -1

OpenStudy (anonymous):

S(n) = a1 (r^n - 1)/(r-1)

OpenStudy (anonymous):

got it?

OpenStudy (anonymous):

What do you mean +a10?

OpenStudy (anonymous):

\[2^{10}\] or \[a^{10}\]? if it is \[1+2+4+8+...+2^{10}\] answer is \[2^{11}-1\]

OpenStudy (anonymous):

i think its the tenth term

OpenStudy (anonymous):

well if it is the tenth term answer would be \[2^{10}-1\] yes?

OpenStudy (anonymous):

ugh idk.. this is SO hard to me.!

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