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evaluate the series 1+2+4+8+....+a10
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1(2^9 - 1)/2 -1
S(n) = a1 (r^n - 1)/(r-1)
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What do you mean +a10?
\[2^{10}\] or \[a^{10}\]? if it is \[1+2+4+8+...+2^{10}\] answer is \[2^{11}-1\]
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i think its the tenth term
well if it is the tenth term answer would be \[2^{10}-1\] yes?
ugh idk.. this is SO hard to me.!
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