Question

(4p^2+4p)/28p^2+16p
simplify by removing factors of 1

Answer 1

\[p(4p+4)/p(28p+16)\]
the p's outside the parentheses will cancel out because p/p = 1
leaving you with
\[(4p+4)/ (28p+16)\]
then you can take out coefficients
\[4(p+1)/4(7p+4)\]
since 4/4 = 1 as well it cancels to:
\[(p+1)/(7p+4)\]