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Mathematics 19 Online
OpenStudy (anonymous):

x+3y≤9 3x+y≤9 x≥0 y≥0

OpenStudy (anonymous):

Are we to solve for x and y?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

it is suppose to be graphed but i dont know how to attach a graph chart

OpenStudy (anonymous):

ah then what are you trying to figure out on the graph?

OpenStudy (anonymous):

just graph?

OpenStudy (anonymous):

are you finding the area enclosed?

OpenStudy (anonymous):

above the x -axis and to the right of the y - axis so in quadrant I below the line x+3y=9 and also below 3x+y=9

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