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Mathematics
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x+3y≤9 3x+y≤9 x≥0 y≥0
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Are we to solve for x and y?
yes
it is suppose to be graphed but i dont know how to attach a graph chart
ah then what are you trying to figure out on the graph?
just graph?
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are you finding the area enclosed?
above the x -axis and to the right of the y - axis so in quadrant I below the line x+3y=9 and also below 3x+y=9
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