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Solve for x: l 3x+19 l = 13
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\[|3x+19|=13\] solve two equations \[3x+19=13\] or \[3x+19=-13 \]
first one is \[3x+19=13\] \[3x=13-19=-6\] \[x=\frac{-6}{2}=-3\]
second one is \[3x+19=-13\] \[3x=-13-19=-32\] \[x=-\frac{32}{3}\]
so x = -2 right?
yeah my mistake! x = -2 is one solution
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\[3x=-6\] \[x=\frac{-6}{3}=-2\]
second solution is \[3x=-32\] \[x=-\frac{32}{3}\]
there are two solutions
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