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solve the following equations: 1. 5^(x+1)=25^(1-x) 2. log3(x-1)=log3(2x/(1-x))
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for # 1 i got x=1/2 but im not confident
5^(x+1)=5^(2(1-x)) x+1=2-2x 3x=1 x=1/2
2) (x-1)=2x/(1-x) (1-x)^2+2x=0 1+x^2=0 so x is imaginory...no real solution..
damn you are fast. its the same as using log right?
of which one are u talking??
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the first and the second one the log cancle? right?
oh isnt it suppose to be (1-x)^2-2X=0
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