Question

1. 4632.73 = 2000e^0.12(t)
how do i solve for t?

2. 100e^0.05(t)=10e^0.15(t) solve for t

Answer 1

e^.12t=4632.73/2000=2.316365
take log
.12t= ln(2.316365)=0.839999147
t=0.839999147/.12=7

Answer 2

got it?

Answer 3

yes sir

Answer 4

m not sir...

Answer 5

opps sorry so for the other problems should i divide 10 first and take the natural log on both side?

Answer 6

100e^0.05(t)=10e^0.15(t)
100/10=e^(.10(t))
now proceed ..

Answer 7

t = 23?

Answer 8

yes it may...

Answer 9

so you just subtract e^0.05 from e^0.15 is that the rules?