Question

the equation of the tangent to the curve y=root(9-2x^2) at the point where the ordinate and the abscissa are equal is?

Answer 1

see first uve got to find out the point

the condition is
x=y
now solve this with ur given curve and tell me the point

Answer 2

x = root (9 - 2x^2)
x^2 = 3
x = root3, -root3

Answer 3

actually the options are (a)2x+y-3rt 3
b)2x+y+3rt 3
c)2x-y-3rt 3
d)none of these