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A bag contains a total of 20 batteries, of which six are defective. Selecting two at random, without replacement, determine the probability that none of the batteries you select are good. 3/5 3/10 3/38 9/100
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\[\frac{14}{20}\times \frac{13}{19}\]
6/20 times 5/19
i get \[\frac{91}{190}\]
which equals 30/380..now reduce
thats what i got satellite
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oh i am wrong. i thought it said "none are defective" it says "none are good" smurfy is right
it simplifies to 3/38 so it is the third one
i wonder why it does not say "both are defective" to make life easier
lol cuz this class sucks... lmao
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