howdo you evaluate the expression if the number inthe square root has an exponent?

7 years agodivide that exponent by 2 and you are all set

7 years ago\[\sqrt{x^{16}}= x^8\]

7 years agothanks (:

7 years agowhat if it has an exponent 3 befor the equation? haha sorry i dont know the right words

7 years ago\[\sqrt{x^3}\] like this?

7 years agono.its right beforethe squareroot

7 years ago\[3\sqrt{x}\]?

7 years agoyes (:

7 years agoThen it is as simplified as it can be.

7 years agoso i just leave it like that?

7 years agoYes, Unless your problem specifically ask for something else

7 years agothankyou somuch! (:

7 years agoYou're welcome

7 years agookay.onemorequestion. the equation says ^3squareroot(n^75). so does the 3 meani just leave it alone or divide by 2?

7 years ago\[3\sqrt{n^{75}}\]?

7 years agoyeah

7 years agoTry using the "Equation" button under the box where you are typing. However, if I understood correctly, you have: \[\sqrt[3]{n^{75}}\]

7 years ago\[3n^{75/2}\]

7 years agoooh gosh, i feel dumb now. haha im new to this placde... but yeah..and thanks

7 years agoIf it is a cube root \[\sqrt[3]{n^{75}}\] you would divide the exponent by 3 n^(75/3)

7 years agoFor future reference a square root is the same as raising to the (1/2) power A cubed root is raising to the (1/3) power, etc.

7 years agothankyou guys so much! (:

7 years agoFor instance: \[9^{0.5}=\sqrt9=3\]

7 years ago