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how to solve for x if the equetion is 3(x-2)squre =9
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first divide by 3 (x-2)^2=9
*=3 RHS ?
do (x-2)(x-2) and you get x^2-4x+4=9 then subtract 9 to make it x^2-4x-5
so what is the answer
nope the answer is
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oh just kidding!
(x-2)^2 = 3 x-2 = +/- root 3 so x = 2 +/- root 3
\[x=2\pm \sqrt{3}\]
ya i kinda messed up sorry :/
that's okay
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