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OpenStudy (anonymous):
how do you solve 2lnx+3ln2=5 ?
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myininaya (myininaya):
2lnx=5-3ln2 lnx=1/2*(5-3ln2) x=e^(.5*(5-3ln2))
OpenStudy (anonymous):
ln[x²·2³]= 5 --> 8x²= e^5 --> x²= 1/8· e^5 and x>0 --> x= √2/4 ·e^(5/2)~ 4.3071....
OpenStudy (anonymous):
hello mininaya!
myininaya (myininaya):
hey
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