Ask your own question, for FREE!
Mathematics
OpenStudy (anonymous):

how do I find the domain of a square-root function?

8 years ago
myininaya (myininaya):

if is in the numerator you want the inside to be bigger than or equal to zero if the is in the denominator you want the inside to be bigger than zero

8 years ago
OpenStudy (anonymous):

What is the function specifically? There are multiple ways for different functions.

8 years ago
myininaya (myininaya):

f(x)=sqrt{x+1} domain is given by x+1>=0 g(x)=1/sqrt{x+1} domain is given by x+1>0

8 years ago
OpenStudy (anonymous):

\[y=\sqrt{x+6}\]

8 years ago
OpenStudy (anonymous):

well because the inside of the radical cannot be a negative, x goes from -6 to infinite, because I do not see any other restrictions

8 years ago
myininaya (myininaya):

you find domain by doing x+6>=0

8 years ago
OpenStudy (anonymous):

then I subtract 6 from both sides?

8 years ago
myininaya (myininaya):

yes and you will get x>=-6 which is what quantabee said

8 years ago
OpenStudy (anonymous):

Ok Thank you!

8 years ago
Can't find your answer? Make a FREE account and ask your own question, OR you can help others and earn volunteer hours!