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OpenStudy (anonymous):

how do I find the domain of a square-root function?

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myininaya (myininaya):

if is in the numerator you want the inside to be bigger than or equal to zero if the is in the denominator you want the inside to be bigger than zero

OpenStudy (anonymous):

What is the function specifically? There are multiple ways for different functions.

myininaya (myininaya):

f(x)=sqrt{x+1} domain is given by x+1>=0 g(x)=1/sqrt{x+1} domain is given by x+1>0

OpenStudy (anonymous):

\[y=\sqrt{x+6}\]

OpenStudy (anonymous):

well because the inside of the radical cannot be a negative, x goes from -6 to infinite, because I do not see any other restrictions

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myininaya (myininaya):

you find domain by doing x+6>=0

OpenStudy (anonymous):

then I subtract 6 from both sides?

myininaya (myininaya):

yes and you will get x>=-6 which is what quantabee said

OpenStudy (anonymous):

Ok Thank you!

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