Question

What is dy/dx of y=ln(5-x^2)??

Answer 1

dy/dx = -2x/(5-x^2)

Answer 2

The derivative of a logarithmic function y = ln(u) where u is a function:

dy/dx = (1/u)(du/dx)

Answer 3

u=5-x^2
y=log(u)

the chain rule says:
\[dy/dx = (dy/du)(du/dx)\]

dy/du=-2x
du/dx=1/u

finally.

dy/dx = (-2x)(1/u) replacing u
dy/dx = (-2x)(1/(5-x^2))
dy/dx = 2x/(x^2 - 5)

Answer 4

any question?

Answer 5

nope thats great thanks!

Answer 6

np