Mathematics
OpenStudy (anonymous):

Use Logarithmic Differentiation to find dy/dx given that y=(((2x+4)^2)sqrroot(2x-2))/(x+6)

7 years ago
OpenStudy (anonymous):

take the log and simplify your %^&* off you get $\ln(\text{stuff})=2\ln(2x+4) +\frac{1}{2}\ln(2x-2)+\ln(x+6)$

7 years ago
OpenStudy (anonymous):

then take the derivative which is now easy you get $\frac{4}{2x+4}+\frac{1}{2x-2}-\frac{1}{x+6}$

7 years ago
OpenStudy (anonymous):

typo on first line last term should be $-\ln(x+6)$

7 years ago
OpenStudy (anonymous):

now multiply by original function and you are done

7 years ago
OpenStudy (anonymous):

sweet thanks man caught one thing u didnt do though 4/2x+4 = 2/x+2 but thank you so much :D:D:

7 years ago
OpenStudy (anonymous):

maybe typos here but you get the idea. take the log, simplify using properties of the log, then take the derivative and then multiply by the original function. don't forget the chain rule!

7 years ago
OpenStudy (anonymous):

eww... chain rule... gah i hate differentiation

7 years ago