Question

How do I integrate sin^{2} x

Answer 1

First convert sin-squared-x to its double-angle identity: 1/2[1-cos(2x)]

Then integrate that expression by conventional methods to obtain the answer:

x/2 - sin(2x)/4

Answer 2

sin ^2 x = (1 - cos2x) / 2

Answer 3

Thanks

Answer 4

And cos^{2} x =1/2(cos(2x)+1)
is that right

Answer 5

yepp thats right

Answer 6

Thanks

Answer 7

:):)

Answer 8

hi eliza, they may have forgotten the integral of dx=x
so
integral of sin^{2} x dx
=integral of (1/2)(1-cos2x)dx
= (1/2)(x-sin2x) +C

Answer 9

integral of sin^{2} x dx
=integral of (1/2)(1-cos2x)dx
= (1/2)(x-sin2x) +C answer....

Answer 10

did you get it eliza?

Answer 11

therefore
integral of sin^{2} x dx
=integral of (1/2)(1-cos2x)dx
= (1/2)(x-sin2x) +C or
=(1/2)(x-2sinxcosx)+C or
=(x/2 - sinxcosx)+C ans....

Answer 12

Thanks yeah sorry I know how to integrate by parts I was just being silly and forgetting the other identity