Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lalaly):
First convert sin-squared-x to its double-angle identity: 1/2[1-cos(2x)]
Then integrate that expression by conventional methods to obtain the answer:
x/2 - sin(2x)/4
OpenStudy (anonymous):
sin ^2 x = (1 - cos2x) / 2
OpenStudy (anonymous):
Thanks
OpenStudy (anonymous):
And cos^{2} x =1/2(cos(2x)+1)
is that right
OpenStudy (lalaly):
yepp thats right
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Thanks
OpenStudy (lalaly):
:):)
OpenStudy (anonymous):
hi eliza, they may have forgotten the integral of dx=x
so
integral of sin^{2} x dx
=integral of (1/2)(1-cos2x)dx
= (1/2)(x-sin2x) +C
OpenStudy (anonymous):
integral of sin^{2} x dx
=integral of (1/2)(1-cos2x)dx
= (1/2)(x-sin2x) +C answer....
OpenStudy (anonymous):
did you get it eliza?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
therefore
integral of sin^{2} x dx
=integral of (1/2)(1-cos2x)dx
= (1/2)(x-sin2x) +C or
=(1/2)(x-2sinxcosx)+C or
=(x/2 - sinxcosx)+C ans....
OpenStudy (anonymous):
Thanks yeah sorry I know how to integrate by parts I was just being silly and forgetting the other identity