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f(g(h(-2))) f(x)=x^2 g(x)=2x-1 h(x)=3x+7
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gh(x)=6x+14-1 fgh(x)=(6x+13)^2 fgh(-2)=-12+13)^2=1^2=1
h(-2)=-6+7=1 g(1)=2-1=1 f(g(h(-2)))=f(1)=1
h(-2)=- 6+7=1 g(1)=1 f(1)=1 so f(g(h(-2))=1
so its 1?
yehh
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yes
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