Question

solve by completing the square

Answer 1

x^2 +2x -8=0

(x+1)^2 - 1-8=0

Answer 2

x^2 +4x -5=0

(x+2)^2 - 4-5=0

Answer 3

first one as folows:

shift the constant to RHS
x^2 + 2x = 8
add square of half of the coefficient of x to both sides
x^2 + 2x + (1)^2 = 8 + (1)^2
LHS becomes (x + 1)^2
(x + 1)^2 = 9
taking squareroot of both sides
x + 1 = root9
x + 1 = +/- 3
shifting 1 to RHS
x = -1 +/- 3
so x = -1-3 = -4 and x = -1 +3 = 2

Answer 4

You can follow the same process for the next one....

If u need help tell me....

Answer 5

okay thank you

Answer 6

pls click GOOD ANSWER button if u r satisfied with the answer ( :{)