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convert to logarithmic equation 5\[^{-3}\]= 1/125
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5^{-3}\] =1/125
5^{-3}\] =1/125
its not coming out right
right
5^-3=1/125
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I'm not sure how they want you to express it as a logarithmic equation..
log ( 1/125) = -3 5
Because when you raise 5 to the power -3 , you get 1/125
logs are simply an expression of exponents. \(5^{-3}=\frac{1}{125} \iff \left(\frac{1}{5}\right)^3=\frac{1}{125}\)
\[log_{1/5}(3)=1/125\] is the best I can make out of it, but I cant recall if we are allowed to have a rational base, cant see any reason whynot tho
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got that backwards...
\[log_{1/5}(1/125)=3\]
or just as well; \[log_{5}(1/125)=-3\]
Sure, or \[-3log(5) = log(1) - log(125)\] Or all kinds of other options..
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