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OpenStudy (anonymous):
convert to logarithmic equation 5\[^{-3}\]= 1/125
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OpenStudy (anonymous):
5^{-3}\] =1/125
OpenStudy (anonymous):
5^{-3}\] =1/125
OpenStudy (anonymous):
its not coming out right
OpenStudy (a_clan):
right
OpenStudy (anonymous):
5^-3=1/125
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OpenStudy (anonymous):
I'm not sure how they want you to express it as a logarithmic equation..
OpenStudy (a_clan):
log ( 1/125) = -3 5
OpenStudy (a_clan):
Because when you raise 5 to the power -3 , you get 1/125
OpenStudy (amistre64):
logs are simply an expression of exponents. \(5^{-3}=\frac{1}{125} \iff \left(\frac{1}{5}\right)^3=\frac{1}{125}\)
OpenStudy (amistre64):
\[log_{1/5}(3)=1/125\] is the best I can make out of it, but I cant recall if we are allowed to have a rational base, cant see any reason whynot tho
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OpenStudy (amistre64):
got that backwards...
OpenStudy (amistre64):
\[log_{1/5}(1/125)=3\]
OpenStudy (amistre64):
or just as well; \[log_{5}(1/125)=-3\]
OpenStudy (anonymous):
Sure, or \[-3log(5) = log(1) - log(125)\] Or all kinds of other options..
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