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Mathematics 44 Online
OpenStudy (anonymous):

what is the derivative of sin^2x+tan(theta)

OpenStudy (asadkarim7):

2cos 2x + cosec (theta)

OpenStudy (amistre64):

[sin^2(x)+tan(t)]' = [sin^2(x)]'+[tan(t)]' [sin^2(x)]' = sin(x)cos(x) [tan(t)]' = sec^2(t)

OpenStudy (amistre64):

if I read it right; we get... sin(x)cos(x) + sec^2(t)

OpenStudy (amistre64):

or more accuratley sin(x)cos(x).x' + sec^2(t).t' ; where x' and t' are derived with respect to some oter variable

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