Question

what is the derivative of sin^2x+tan(theta)

Answer 1

2cos 2x + cosec (theta)

Answer 2

[sin^2(x)+tan(t)]' = [sin^2(x)]'+[tan(t)]'

[sin^2(x)]' = sin(x)cos(x)

[tan(t)]' = sec^2(t)

Answer 3

if I read it right;

we get... sin(x)cos(x) + sec^2(t)

Answer 4

or more accuratley

sin(x)cos(x).x' + sec^2(t).t' ; where x' and t' are derived with respect to some oter variable