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find the value of b
in the equation 25^b = 5square root 5
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actually I want to thank you for this question, It refreshed my memory.
25^b = 5(sq.rt.5)
log (25)^b = log 5(sq.rt.5)
b*log (25) = log 5(sq.rt.5)
b= (log 5(sq.rt.5)) / (log (25)
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