Mathematics OpenStudy (anonymous):

lim x->-infinti of sqrt (3x^2+6) / 5-2x OpenStudy (anonymous):

$\lim_{x \rightarrow -\infty} \sqrt{3x ^{2+6}} \div 5-2x$ OpenStudy (anonymous):

$\frac{\sqrt{3}}{2}$ myininaya (myininaya):

$\frac{\sqrt{3x^2+6}}{5-2x}$ OpenStudy (anonymous): OpenStudy (anonymous):

so sqrt3/-2? OpenStudy (anonymous):

no because you are going to $-\infty$ yes? myininaya (myininaya):

$\frac{\sqrt{3x^2+6}}{5-2x}*\frac{\frac{1}{x}}{\frac{1}{x}}$ =$\frac{\sqrt{\frac{3x^2}{x}+\frac{6}{x}}}{{\frac{5}{x}-\frac{2x}{x}}}$ OpenStudy (anonymous):

if you were going to $\infty$ you would be right. but you are going to $-\infty$ so both top and bottom are positive OpenStudy (anonymous):

?? myininaya (myininaya):

$\frac{\sqrt{3x+\frac{6}{x}}}{\frac{5}{x}-2}$ OpenStudy (anonymous):

ohh..so its - infinit? myininaya (myininaya):

right it goes to -inf OpenStudy (anonymous):

dunno but that looks like what you wrote yes? OpenStudy (anonymous):

lim x->-infinti of sqrt (3x^2+6) / 5-2x OpenStudy (anonymous):

i think so? myininaya (myininaya):

of x->-inf didn't see the negative OpenStudy (anonymous):

ok in that case it is $\frac{\sqrt{3}}{2}$ fer sure myininaya (myininaya):

i don't agree OpenStudy (anonymous):

hello myininaya! myininaya (myininaya):

oops i do agree OpenStudy (anonymous):

well you are probably right and i am wrong as usual OpenStudy (anonymous):

lol so step by step..the powers dont match..so i thought it wud jus b 0 or doesnt exisit? OpenStudy (anonymous):

oh then if you agree i disagree! lol myininaya (myininaya):

i divided top by wrong thing it is suppose to be sqrt(x^2) OpenStudy (anonymous):

forget that noise (no offence) myininaya (myininaya):

i will write this out again in prettiness okay OpenStudy (anonymous):

okay:) OpenStudy (anonymous):

look. denominator is poly of degree 1 yes? numerator is not a poly but for limit purposes it might as well be. nothing matter but highest degree OpenStudy (anonymous):

forget everything after the $\sqrt{3x^2}=\sqrt{3}x$ myininaya (myininaya):

$\frac{\sqrt{3x^2+6}}{5-2x}*\frac{\frac{1}{x}}{\frac{1}{x}}=\frac{\sqrt{\frac{3x^2+6}{x^2}}}{\frac{5}{x}-\frac{2x}{x}}$ OpenStudy (anonymous):

so you get $\frac{\sqrt{3}x}{-2x}=\frac{\sqrt{3}}{-2}$ myininaya (myininaya):

$\frac{\sqrt{3+\frac{6}{x^2}}}{\frac{5}{x}-2}$ OpenStudy (anonymous):

not that my esteemed colleague is wrong, it is just that you can do this with your eyes myininaya (myininaya):

6/x^2->0 5/x->0 OpenStudy (anonymous):

but isnt it $\sqrt{3x ^{2}}$ OpenStudy (anonymous):

anyway i should be quiet because myininaya is way smarter than i am OpenStudy (anonymous):

right and $\sqrt{3x^2}=\sqrt{3}x$\] OpenStudy (anonymous):

what about the power to 2? myininaya (myininaya):

not true satellite OpenStudy (anonymous):

$\sqrt{x^2}=|x|$ OpenStudy (anonymous):

what is not true? myininaya (myininaya):

since x->-inf, f(x)->sqrt{3}/2 if x->inf, f(x)->-sqrt{3}/2 that im smater (its not true) OpenStudy (anonymous):

way smarter OpenStudy (anonymous):

both of u r smart! im not OpenStudy (anonymous):

but i did cross the 1000 mark! no one threw a party :( myininaya (myininaya):

i threw a party for you and i forgot to invite you sorry OpenStudy (anonymous):

!!! no bike rides for you! OpenStudy (anonymous): myininaya (myininaya):

then you thought correctly! OpenStudy (anonymous):

didnt u say the opp of tht previosuly? OpenStudy (anonymous): myininaya (myininaya):

oops i didn't see you change the signs sorry OpenStudy (anonymous):

ohh right..4got abt tht negative OpenStudy (anonymous):

denominator is 5 - 2x so as x -> infinity this goes to - infinity and vice versa myininaya (myininaya):

if x is negative and there is a negative sign in front of it that number would be positive right? OpenStudy (anonymous):

so the ans is -3/2? OpenStudy (anonymous):

i am taking my 1005 medals and going to bed. no $\frac{\sqrt{3}}{2}$ OpenStudy (anonymous):

ohhok...i think i got it OpenStudy (anonymous):

good. don't forget the coefficient in the numerator is $\sqrt{3}$ not 3 OpenStudy (anonymous):

alrigty:) thanks a ton! OpenStudy (anonymous):

yw myininaya (myininaya):

sanhitha you forgot to ask him if he is indian im disappointed in you myininaya (myininaya):

jk OpenStudy (anonymous):

lol..dude! i only asked 2 ppl includin u OpenStudy (anonymous):

haha OpenStudy (anonymous): OpenStudy (anonymous):

haha thts funny OpenStudy (anonymous):

woof

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