Question

Determine dy/dx: y=xe^-x^2. I got y'=-xe^-x^2+e^-x^2. Am i correct?

Answer 1

\[\frac{d}{dx}xe^{-x^2}\]?

Answer 2

then no the answer is wrong. should be
\[e^{-x^2}-2x^2e^{-x^2}\]

Answer 3

via product rule and chain rule

Answer 4

\[\frac{d}{dx}e^{-x^2}=-2xe^{-x^2}\]

Answer 5

f(x)=x*e^u\[ dy/dx=e^u + x *u \prime*e^u\]