Question

solve by factoring
2x^2+3x=0

Answer 1

x(2x+3)=0
x=0,-3/2

Answer 2

there's supposed to be 2( )

Answer 3

2x^2 + 3x
take x as common
x(2x+3)=0
either x=0 or 2x+3=0
now simplify 2x+3=0
transpose 3 to RHS u would get:
2x=-3
divide both sides by 2 u would get:
2x/2=-3/2
x=-3/2
hence it has two solutions these are:
x=0 and x=-3/2

Answer 4

understood tiny dancer or any problem

Answer 5

its supposed to be shaped like this: ( ) ( )

Answer 6

x(2x+3)=0
2x+3=0
x=-3/2

Answer 7

TinyDancer - I understand what you're asking. In this case, you are factoring out the x because there are only 2 terms, not 3. When there are 2 terms the ( ) ( ) format will not work.

Answer 8

oh okay