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OpenStudy (anonymous):
=(w-3)(w+1)/(w-1)^2 *(w-1)/(w-3)
cancel out (w-1) & (w-3)
OpenStudy (anonymous):
=(w+1)/(w-1)
OpenStudy (anonymous):
Once you multiply you get
(w^3-2w^2-3w-w^2+2w+3)/(w^3-2w^2+w-3w^2+6w-3) Then combine like terms to get
(w^3-3w^2-w+3)/(w^3-5w^2+7w-3)
OpenStudy (anonymous):
Pfft inik did it the easier way....why you so good!? XD
OpenStudy (anonymous):
i'm lazy... hate long multiplications :)
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OpenStudy (anonymous):
XD My pre-cal teacher does a bunch of the long way ones, he's evil.
OpenStudy (anonymous):
said answer was wrong
OpenStudy (anonymous):
oups!
let's check!
OpenStudy (anonymous):
nope... still getting:
(w+1)/(w-1)
did you check original problem?
OpenStudy (anonymous):
it's (w+1) divide by (w-1)...
please check again. I do not see any mistakes
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OpenStudy (anonymous):
it wanted w-1/w-3
OpenStudy (anonymous):
how?
did you see the solution above?
w^2-2w-3=(w-3)(w+1)
so, you have to have (w+1) in answer...
can't get it. check with your teacher... something is wrong