w^2-2w-3/w^2-2w+1 * w-1/w-3 multiply and simplify
=(w-3)(w+1)/(w-1)^2 *(w-1)/(w-3) cancel out (w-1) & (w-3)
Once you multiply you get (w^3-2w^2-3w-w^2+2w+3)/(w^3-2w^2+w-3w^2+6w-3) Then combine like terms to get (w^3-3w^2-w+3)/(w^3-5w^2+7w-3)
Pfft inik did it the easier way....why you so good!? XD
i'm lazy... hate long multiplications :)
XD My pre-cal teacher does a bunch of the long way ones, he's evil.
said answer was wrong
oups! let's check!
nope... still getting: (w+1)/(w-1) did you check original problem?
it's (w+1) divide by (w-1)... please check again. I do not see any mistakes
it wanted w-1/w-3
how? did you see the solution above? w^2-2w-3=(w-3)(w+1) so, you have to have (w+1) in answer... can't get it. check with your teacher... something is wrong
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