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Find the exact solutions to each equation for the interval 0<=x<2pi. 2cos^2 x-3 cos x+1=0
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hey yotis the question before they missed a solution
let u=cosx 2u^2-3u+1=0 2u^2-2u-u+1=0 2u(u-1)-(u-1)=0 (u-1)(2u-1)=0 u=1 u=1/2 but remember u=cosx cosx=1 so x=0,2pi cosx=1/2 so x=pi/3, 5pi/3
so theirs four solutions to this one?
we don't include 2pi if x<2pi
we include 2p if x<=2pi
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so its just 0, pi/3 and 5pi/3 ?
yes! :)
alright, thanks.
haha that pic is pretty gay ill admit it but yeah i linked it to my facebook.
oh i was going to say u guys look cute (dont worry im not a guy)
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haha thanks
lol
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