integral question?!?!?hellpp

if it is given that \[\int\limits_{2}^{4} x ^{3}dx=60 and \int\limits_{2}^{4}xdx=6 and \int\limits_{2}^{4}dx=2\]

if u had 2 find....a.\[\int\limits_{2}^{2}x ^{3}dx? and \int\limits_{2}^{4}15dx? and \int\limits_{2}^{4}(x ^{4}+4)?\]

the second one is 15*2=30

I'm not sure I understand the question.

i think u got the 2nd one right...its jus the top n bottom parts tht change tht confuse me..

basically..use only the given info,,n sum rules to find it

the third one you have to separate the integrals into x^4 and 4.... then you do 60*6 + 2*4 = 368

how do u put numbers on brackets after u integrate?

oh! first one equals 0 because there's a rule that says if the upper and lower bounds are the negative opposites of each other, the integral equals 0.

ohhok..i think u got all of them..thank u soo much!!

:)

first one is a zero, next one is 30

last one: 1032/5

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