Question

Find y' when y=e^sinhx cosh (3x)

Answer 1

sinhx = (e^x - e^-x)/2. (sinhx)' = (e^x + e^-x)/2 = cosh(x).
(cosh(x))' = (e^x - e^-x)/2 = sinhx.
So y' = e^sinhx cosh (3x)*( coshx*cosh3x + sinhx*3sinh3x ).

Answer 2

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