Question

Solve the compound inequality. Express the solution using interval notation.
n-4/3>=1 and 6n-3/3<=21

Answer 1

\[n-\frac{4}{3}\geq1\]
\[n\geq 1+\frac{4}{3}\]
\[n\geq \frac{7}{3}\]

Answer 2

oh wait

Answer 3

i bet this is
\[\frac{n-4}{3}\geq 1\] yes?

Answer 4

in which case
\[n-4\geq 3\]
\[n\geq7\]

Answer 5

\[\frac{6n-3}{3}\leq21\]
\[6n-3\leq 63\]
\[6n\leq 66\]
\[n\leq 11\]

Answer 6

so you have
\[7\leq n \leq 11\]

Answer 7

interval notation is [7,11]