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Solve the compound inequality. Express the solution using interval notation. n-4/3>=1 and 6n-3/3<=21
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\[n-\frac{4}{3}\geq1\] \[n\geq 1+\frac{4}{3}\] \[n\geq \frac{7}{3}\]
oh wait
i bet this is \[\frac{n-4}{3}\geq 1\] yes?
in which case \[n-4\geq 3\] \[n\geq7\]
\[\frac{6n-3}{3}\leq21\] \[6n-3\leq 63\] \[6n\leq 66\] \[n\leq 11\]
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so you have \[7\leq n \leq 11\]
interval notation is [7,11]
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