Question

To rationalize then simplified:
two squareroot of x minus three squareroot of y all divided by squareroot of x plus square root of y
Thank:D

Answer 1

2root x - 3root y / root x + root y
rational denominator by multuplying by (rootx - rooty)
=(2root x - 3root y) (root x - root y) / (x-y)
=(2x -2root x * root y - 3 root y * root x + 3 y / (x-y)
=(2x +6xy + 3y) / (x - y)

Answer 2

not quite sure of this just rechecking

Answer 3

Wait it works Thanks

Answer 4

no sorry! the last line is wrong

Answer 5

other way around?

Answer 6

how do u mean it works

Answer 7

Well, i have this online course you see, and this answer fits the amount of blocks it gives

Answer 8

here look at this

Answer 9

-2root x * root y - 3 root y * root x is not = 6xy it = 6 root(xy)

Answer 10

thats the one

(2x +6root(xy) + 3y) / (x - y)

Answer 11

yep that checks out

Answer 12

Thanks:D

Answer 13

yw

Answer 14

How do you know how to do this? Everybody in my group is inadeuquate to solve these

Answer 15

'root6' and similar are called surds and u need to know how to manipulate them.
the wolfram math sites will have info about them

Answer 16

\[\left(2 \sqrt{x}-3 \sqrt{y}\right)\left(\sqrt{x}-\sqrt{y}\right)=2 x-5 \sqrt{x} \sqrt{y}+3 y \]Is there an error at untitled.jpg?

Answer 17

What do you mean error?

Answer 18

yes u are rob right its - 5 root ( xy) not 6 root (xy)

Answer 19

Here is another one if you want?

Answer 20

the jpg is wrong

Answer 21

the first one i know it is i fixed it

Answer 22

ok
in the next one you take out the surd (sqrt 7 + 2) by multiplying by its complement
this is (sqrt 7 - 2)
(sqrt 7 + 2) * (sqrt 7 - 2) = 7 + 2 sqrt 7 - 2 sqrt 7 - 4 = 3
you also have to multiply the top by (sqrt 7 + 2)

so we get 12(sqrt 7 - 2) / 3
= 4(sqrt7 - 2)
or 4sqrt 7 - 8

Answer 23

hope i havent made another boob !

Answer 24

Oh i gotcha, thanks

Answer 25

oh oh!

Answer 26

Jimmyrep's answer looks ok.\[\left(\frac{12}{\sqrt{7}+2}\right)\left(\frac{\sqrt{7}-2}{\sqrt{7}-2}\right)=\frac{12\left(\sqrt{7}-2\right)}{3}=4 \sqrt{7}-8 \]

Answer 27

tell me rob how do u do the maths symbols using Equation box or other?

Answer 28

I use Mathematic 8 for solving problems on this site. In the program there is an option to copy answers in LaTex form. So it is simply a matter of a copy and paste into this sites "Sigma" Equation box.

Answer 29

right - ill look at that thanx

Answer 30

Your welcome.

Answer 31

Sorry. The program's name is Mathematica 8, not Mathematic 8.

Answer 32

ok