Find the equation of the line that contains the point (5, 8) and has a slope of 1/2. (5, 8) and m=1/2 help?

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OpenStudy (anonymous):

Point slope form:
Given m and \[\(x_\0\,y_\0\)\]
Then the equation of a line is given by:
\[y-y_\0\=m(x-x_\0\)\]
Plug in and solve for y.

OpenStudy (bahrom7893):

y - y1 = M (x - x1)
y - 8 = (1/2) ( x - 5)
y = (1/2)x - 5/2 + 8
y = (1/2)x - 1/2

OpenStudy (amistre64):

your latex looks wierd, did it format right on your screen?

OpenStudy (anonymous):

Nah :/
\[(x_0,y_0)\]
Then use:
\[y-y_0=m(x-x_0)\]

OpenStudy (anonymous):

There we go :)

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OpenStudy (amistre64):

thats better :)

OpenStudy (anonymous):

Yeah mine did that too :/ Idk what that was about.

OpenStudy (anonymous):

Ok, apparently that answer is wrong, here is the question word for word
"Find the equation of the line containing the give point and slope. (5,8) and m=1/2

OpenStudy (amistre64):

which form of the equation are they after?

OpenStudy (bahrom7893):

hmm that answer is right, maybe you need to pull out 1/2:
y = (1/2)( x - 1 )

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