Find the equation of the line that contains the point (5, 8) and has a slope of 1/2. (5, 8) and m=1/2 help?

Point slope form: Given m and \[\(x_\0\,y_\0\)\] Then the equation of a line is given by: \[y-y_\0\=m(x-x_\0\)\] Plug in and solve for y.

y - y1 = M (x - x1) y - 8 = (1/2) ( x - 5) y = (1/2)x - 5/2 + 8 y = (1/2)x - 1/2

your latex looks wierd, did it format right on your screen?

Nah :/ \[(x_0,y_0)\] Then use: \[y-y_0=m(x-x_0)\]

There we go :)

thats better :)

Yeah mine did that too :/ Idk what that was about.

Ok, apparently that answer is wrong, here is the question word for word "Find the equation of the line containing the give point and slope. (5,8) and m=1/2

which form of the equation are they after?

hmm that answer is right, maybe you need to pull out 1/2: y = (1/2)( x - 1 )

y = 1/2 x -1/2(5) +8

yah its really vague on what they want.

y = \(\frac{x+11}{2}\) is one way

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