For the following equation describe A) up or down b) vertex c) axis of symetry D) min or max and E) graph y= -x^2+5x-4
A quadratic equation in standard form looks like ax^2 + bx+c, where a, b and c are the coefficients. If a is positive, the parabola opens upward and the vertex is at a minimum. If a is negative, the vertex is a maximum. To find the vertex use x = -b/2a. then find f(-b/2a) which equals the y value at the vertex. the axis of symmetry runs through the vertex so the equation would be x = -b/2a, which you already found. to graph the equation, set it equal to zero and find the zeros of the equation (by the quadratic formula, by factoring or by completing the square, depending upon the equation to be solved.
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