Question

(x-2)^2 + (y-2)^2=4 is a circle. Write the formula for the upper half of the circle. i.e. y=f(x) and what is the domain

Answer 1

Foil everything out

Answer 2

x^2-4x+4+y^2-4y-4=4

Answer 3

x^2-4x+y^2-4y=4

Answer 4

Solve for y
y=sqrt(4-(x-2)^2)+2
You get a plus/minus in the square root but you want the top half so make it positive.

Answer 5

The the domain is where 4-(x-2)^2>=0
4>=(x-2)^2
+/-2>=x-2
x>=2+/-2
2>=x>=0

Answer 6

hm i always thought the domain was a coordinate