Question

how do I solve this problem? Find the domain of the following: f(x) = x over x-squared - 3x - 10.

Answer 1

the denominator is a quadratic right?
X^2-3x-10

Answer 2

yes, it is

Answer 3

so set it to = 0 and apply the quadratic formula

Answer 4

so for a=1 b=-3 and c=-10 ?

Answer 5

Yup!

Answer 6

i got 3/2 +or -7/2

Answer 7

wow, i haven't answered it yet, but thank you for your answer. I have on more question. How to i solve f(x) = -2 over square root of 4+x ?

Answer 8

so for the 1st one its X cant be 5 or 2 got it?

Answer 9

huh?

Answer 10

i meant thats the answer to the first problems. try to work it out and see if you understand it

Answer 11

ok

Answer 12

\[-2/\sqrt{4+x}\]

Answer 13

is that the second problem?

Answer 14

yes

Answer 15

you cant have a negative square root so set the squareroot of \[\sqrt{4+x}\] greater or equal to zero

Answer 16

i mean 1

Answer 17

is the answer -3? for problem 2?

Answer 18

yup! it means that x have to be greater or equal to -3

Answer 19

wow, thank you :)

Answer 20

does it make sense?

Answer 21

yes, problem two does. I tried to solve problem 1 and i got \[x = 3/2 \pm \sqrt{151} / 2 i\]

Answer 22

do i deserve a medal? =)

Answer 23

:) how do i give you a medal?

Answer 24

\[-b \pm \sqrt{b^2-4ac}\] all over 2a

Answer 25

click good answer

Answer 26

i did

Answer 27

thank you

Answer 28

you might plug something wrong

Answer 29

i approximated the answer to find what x equals and i got x = 7.64 and x = -4.64. is that what you meant by 7 and -5?

Answer 30

no no

Answer 31

ok so b = -3 a = 1 c = -10

Answer 32

yes

Answer 33

\[3\pm \sqrt{9-4(1)(-10)}\]

Answer 34

sorry i donw know how to do the all over sign

Answer 35

ok. it's over 2 right?

Answer 36

yup!

Answer 37

\[3\pm \sqrt{49}\]

Answer 38

right?

Answer 39

i see what i did wrong

Answer 40

\[3/2\pm7/2\] sqrt of 49 = 7

Answer 41

yes, i got it. Thank you :) I have to go now.

Answer 42

welcome