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How do i find the derivative of (6x / the square root of x squared + 5)?
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Quotient rule: Assuming \[f(x)=\frac{6x}{\sqrt{x^2+5}}\] Then: \[f'(x)=\frac{6(\sqrt{x^2+5})-(6x)(\frac{1}{2})(2x)(x^2+5)^{\frac{-1}{2}}}{(\sqrt{x^2+5})^2}\] Then you can simplify it from there.
Refresh if the latex looks bad
orrr, go with the whole f(x+h)-f(x) fiasco :)
I agree with amistre^^
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Builds character :)
if you cant remember the shortcuts; you pretty much dont deserve them ;)
Haha
Thanx
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