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OpenStudy (anonymous):
Solve using the quadratic formula: x^2-3x-18=0
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OpenStudy (anonymous):
It factors to: (x-6)(x+3)=0. So x=6,-3
OpenStudy (anonymous):
what about with the quadratic formula?
OpenStudy (anonymous):
Never mind!
OpenStudy (anonymous):
\[\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
OpenStudy (anonymous):
I got the answer... I was adding incorrectly...
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OpenStudy (anonymous):
ok
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