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how do i write 2x^2+y^2=8 in standard form?
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Isotate Y ---> Y^2 = 2x^2 - 8 ---> Y= ((2x^2 - 8))^(1/2) ----> Y=(2(x^2 -4))(1/2) ---> Y=(2(x-2)(x+4))^(1/2)
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