Can somebody help me figure out, how to graph the below equation?
3x is equal or greater than -y + 3
How can you graph it, when you only have the one point of 3, for the y intercept? How can you tell which way your line needs to go?

Question

anonymous · Answer

$$3x \ge -y+3$$ 
You have to make it of the form $$y \le something$$ 
You graph that line and it'll be that line and the area above that lIne

anonymous · Answer

Sorry
 $$y \ge something $$ and it's the line and the area below it

anonymous · Answer

Let me attach a picture of the graph that the answer key has....it shows the area above the line shaded..

anonymous · Answer

$$3x \ge -y +3$$
$$3x+y \ge +3$$
$$y \ge -3x+3$$
and you can draw the line of $$y=-3x+3$$

anonymous · Answer

And it'll be the area above it sorry I always get confuse

anonymous · Answer

It's because y is greater than or equal to so above because greater numbers are above

anonymous · Answer

but how did they come up with the second point, of 1, on the x axis?

anonymous · Answer

Because if you plug in y=0 into y=-3x+3 you get x=1 right?

Just pretending it's a normal equation not an equality
D'you get it?

anonymous · Answer

My textbook just said something about plugging in 0 for x and y both, to determine whether the origin was part of the equation...but anyway..so I just plug in 0 for y, to determine the second point of the line? Does that work like every time, is it a math rule?

anonymous · Answer

Because I will be trying your method on other problems of this type possibly..

anonymous · Answer

If you plug in y=0 you always get the point that it intersects the x-xis

anonymous · Answer

ok thanks, I'll see if it works for my other problems here.