y=+-/9+x2
what are we to find?
find?
quick answer w/out graph
lol we can draw two graphs
wht v hav to find?
1st graph critical points- when x=0...y=+9 and then when y=0 ....x=-9/2 2nd graph when x=0 ....y=-9 and when y=0...x= +9/2 does that help?
the quick ans. and the graph can u?
ya.just plot the co-ordinates i gave you
y=+-squaroot of 9+x2
ok same procedure il do 1 graph for you... when x= 0 ....y=+squareroot9 when y=0....x = - (squareroot 0f 9)/2 ok 2nd graph for you because you'll definitly give me a medal when y=0....x= (squareroot9)/2 and when x=0...y=-squareroot9
dats the oll ans. sir ?
yes
thank you
y=+-squaroot of 9+x2
GIRL is that 2x or x^2?
x squared
opo
then the previous answer is not correct. wait
ah ok2
when x=0...y=3 when y=0...x=no sol as we cant have a squareroot on -3 2nd case when x=0...y=-3 when y=0.....x=...squareroot3 sorry girl but i didnt notice your notation at first but now i have....fortunately
no probes....huhuhuh sori i dnt know the real ans...2 my own
thank you
lol now you do....and remember practice makes perfect!
huhuhuh i try my best to mke a hit w/ my own performans but i cant huhuhuh
i want to have a high grades....2 my sweat...but how ?
dont loose hope...just keep on practicing.....you are way better than someone who does nothing at all.your effort shall be rewarded with good results believe me
improve your study methods
ok thanks a lot ! may god glory of you !
amen may He bless you with the courage od doing math,strength for never giving up and wisdom of Maths....May you see The Light
huhuhuh i appreciate ur words! anyeong gab nab sim neda !
mmmm thanx altho i dont no wat de rest of zi words min '"anyeong gab nab sim neda""
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