y=+-/9+x2

what are we to find?

find?

quick answer w/out graph

lol we can draw two graphs

wht v hav to find?

1st graph critical points- when x=0...y=+9 and then when y=0 ....x=-9/2 2nd graph when x=0 ....y=-9 and when y=0...x= +9/2 does that help?

the quick ans. and the graph can u?

ya.just plot the co-ordinates i gave you

y=+-squaroot of 9+x2

ok same procedure il do 1 graph for you... when x= 0 ....y=+squareroot9 when y=0....x = - (squareroot 0f 9)/2 ok 2nd graph for you because you'll definitly give me a medal when y=0....x= (squareroot9)/2 and when x=0...y=-squareroot9

dats the oll ans. sir ?

yes

thank you

y=+-squaroot of 9+x2

GIRL is that 2x or x^2?

x squared

opo

then the previous answer is not correct. wait

ah ok2

when x=0...y=3 when y=0...x=no sol as we cant have a squareroot on -3 2nd case when x=0...y=-3 when y=0.....x=...squareroot3 sorry girl but i didnt notice your notation at first but now i have....fortunately

no probes....huhuhuh sori i dnt know the real ans...2 my own

thank you

lol now you do....and remember practice makes perfect!

huhuhuh i try my best to mke a hit w/ my own performans but i cant huhuhuh

i want to have a high grades....2 my sweat...but how ?

dont loose hope...just keep on practicing.....you are way better than someone who does nothing at all.your effort shall be rewarded with good results believe me

improve your study methods

ok thanks a lot ! may god glory of you !

amen may He bless you with the courage od doing math,strength for never giving up and wisdom of Maths....May you see The Light

huhuhuh i appreciate ur words! anyeong gab nab sim neda !

mmmm thanx altho i dont no wat de rest of zi words min '"anyeong gab nab sim neda""

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