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OpenStudy (anonymous):
3x-2y=15 3x+2y=7
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OpenStudy (anonymous):
x=11/3 y=-2
OpenStudy (saifoo.khan):
y=-2 x=11/3
OpenStudy (anonymous):
solve this using simultaneous equations. if you subtract them you get the answers above, understand?
OpenStudy (anonymous):
i.e. y = 3x-2y=15 y = 3x+2y=7 y = 0-4 = 8 y=8/-4 y=-2 Now you have a value for y put that back in the eqn and find x
OpenStudy (anonymous):
like that (3x+2y)+(3x-2y)=15+7 6x=22 x=11/3 same for y
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OpenStudy (anonymous):
(3x+2y)-(3x-2y)=7-15 4y=-8 y=-2
OpenStudy (lalaly):
adding them u get 6x=22 x=11/3 substitute in 2nd equation 11+2y=7 2y=-4 y=-2
OpenStudy (anonymous):
got it??
OpenStudy (anonymous):
\[\sqrt{x+6}=2+\sqrt{x}\]
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