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OpenStudy (anonymous):

3x-2y=15 3x+2y=7

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OpenStudy (anonymous):

x=11/3 y=-2

OpenStudy (saifoo.khan):

y=-2 x=11/3

OpenStudy (anonymous):

solve this using simultaneous equations. if you subtract them you get the answers above, understand?

OpenStudy (anonymous):

i.e. y = 3x-2y=15 y = 3x+2y=7 y = 0-4 = 8 y=8/-4 y=-2 Now you have a value for y put that back in the eqn and find x

OpenStudy (anonymous):

like that (3x+2y)+(3x-2y)=15+7 6x=22 x=11/3 same for y

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OpenStudy (anonymous):

(3x+2y)-(3x-2y)=7-15 4y=-8 y=-2

OpenStudy (lalaly):

adding them u get 6x=22 x=11/3 substitute in 2nd equation 11+2y=7 2y=-4 y=-2

OpenStudy (anonymous):

got it??

OpenStudy (anonymous):

\[\sqrt{x+6}=2+\sqrt{x}\]

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