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OpenStudy (anonymous):
5x^2 + 10
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OpenStudy (anonymous):
what is it equal to?
OpenStudy (anonymous):
noting in mixed factoring
OpenStudy (anonymous):
Oh, you are factoring then you will see that 5 is the common factor in both terms
OpenStudy (anonymous):
but what the whole anwers
OpenStudy (anonymous):
So you factor out 5,and get this 5(x^2+2)
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OpenStudy (anonymous):
i am going to give you and example 5x^2 - 45 the anwers is 5(x+3)(x - 3)
OpenStudy (anonymous):
so first you factor out the 5 5(x^2-9) the factor the parethesis 5(x+3)(x-3)
OpenStudy (anonymous):
so 5(x + 2)(x+2) is the anwers
OpenStudy (anonymous):
no , 5(x^2+2) can't be factored any further
OpenStudy (anonymous):
no that is not how you do it
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OpenStudy (anonymous):
ok, then how do you do it?
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