Question

Solve by the elimination method
0.3x-0.2y=4
0.5x+0.5y=-15/19

Answer 1

x = 7.368

y = -8.947

Answer 2

That one was wrong! :(

Answer 3

do you want the elimination process demonstrated?

Answer 4

the ques? :O

Answer 5

no the answer.

Answer 6

wait, let me chk again.

Answer 7

im getting the same ans! :S

Answer 8

is the ques correct?

Answer 9

yes

Answer 10

It tells you if the answer is correct or not.

Answer 11

:S

Answer 12

Do you want to see the elimination method step by step?

Answer 13

Or are you only interested in the answer?

Answer 14

how can u get this ans radat?

Answer 15

radar*

Answer 16

saifoo.kahn I would like to repeat the steps and you critique the work.

Answer 17

i usd calc to find the answrs! :O

Answer 18

Or anyone else. Here is what I did:
Eq 1: .3x-0.2y=4
Eq 2: .5x+.5y =15/19
Step 1. Multiply Eq1 by 5
becomes: 1.5x-y=20 multiply Eq2 by 3 getting: 1.5x+1.5y=45/19
subtract the latter from the other
1.5x -y = 20
- 1.5x +1.5y=45/19
----------------------
-2.5y =335/19
solve for y

-2.5y 335
------ = -----
1 19

-2.5y (19) =335
-47.5y=335
y=-7052631579

oops I guessed I messed up on the sign the first time. Was their anything wrong with this effort?

Answer 19

* put a decimal point between the 7 and 0 lol

Answer 20

so what is x

Answer 21

substitute the value in y and solve for x

.5x + .5(-7.052631579)=15/19
.5x -3.526315789=.789473684
.5x=4.315789473
x=8.631578946

This again is different from the first solution for x both in sign and value.

Answer 22

rachelgreen3, did you check my work?

Answer 23

the answer was 140/19 -170/19

Answer 24

correct rachiel

Answer 25

rachelgreen3*

Answer 26

i said the same thing.

Answer 27

yes, i was CORRECT! :D

Answer 28

I see now where I erred the second time, i copied the second equation wrong putting a 15/19 when it should of been a -15/19. Makes a big difference.

Answer 29

np Radar... Mistake happen.. (: