Question

This is a Geometry problem attachment included

Answer 1

the segment which is in front of the angle 30 is 6 so the hypotenuse must be 6*2=12
and the other (side)^2 =12^2-6^2=144-36=108
side =sqr108

Answer 2

Pythagorean Theorem

Answer 3

so it must be A

Answer 4

y=12 and x=sqr108=2sqr27

Answer 5

the side in front of angle 30 degrees is 1/2 of hypotenuse

Answer 6

get it?

Answer 7

a lil

Answer 8

A) x = 6root3 and y =12

Answer 9

6=y/2 so y=2*6=12
and to find X we use Pythagorean theorem

Answer 10

Thank you harkirat