Solve the following system of equations for the unknown variables. y = 2x x = 2y – 2
sutitution x = 2y – 2
wait let me check
yeah last answer came up wrong would u like possible answer's?
y=2x sutitution x=2y -2 y=2(2y-2) y=4y-4 4y -y = 4 3y= 4 y = 4/3
now sutitution y =4/3 solve for x x =2(4/3) -2 x=(8/3)-2 x=(8-(2*3))/3 x =(8-6)/3 x= 2/3
here is correct answer
yeah thats the one thank u how do you know when to substitute -2?
what u mean, the frist I solve is correct equation, but when I caculator I was wrong
-2 form this equation x = 2y – 2
im having issues with where ur getting the -2
r u getting now?
i understand the process of getting the answer but do i always use neg two or will it change with different equations?
frist use ; y=2x
and sutitution x = 2y – 2
y=2( ) plug 2y – 2 inside Parentheses and solve
after find y =4/3 use eqution x = 2y – 2 x = 2( ) – 2 plug 4/3 inside Parentheses and solve
2 way can solve * use subtitution *elemate this given value x and y you use sutitution more easy
know what u mean 2x-y=0 -x+2y=2 (this equation time 2) u get -2x+4y=4 -2x+4y=4 Add 2x-y=0 ----------------------- 3y=4 y=4/3 this u mean? answer come up the same
ahh ok see i was confused which method to use substitution seems easier
if u have value x and y better do sutitution more easy if standart from use elemate
cool ive got another one im haven issues with u wana check it out
ok
Solve the following system of equations for the unknown variables. 3x + 3y = 3 -3x – 2z = -11 y + z = -1
solving for x,y,z
u know how to get rid by negative side?
no
this standart from than solve by elemate
give me time this one is hard
yeah i figured out the last two but this one i keep running into problems
Sorry u need u sutitution not elemate y + z = -1 y= -1-z 3x + 3y = 3 (plug y= -1-z in this eqution u get) 3x + 3(-1-z) = 3
can u solve next?
yeah i think so if z=-1 i just plug it into the other equations to get x and y
yes, I think u can do the rest
thanks how did u get so good at math
y + z = -1 (subtitution z= -1) y+(-1) =-1 y -1 = -1 y =-1+1 y= 0
yeah i got x=1 y=0 z=-1
yes
makes sense i think i messed up when i put y=-z-1
let me check, some time I caculator wrong
z=1 not -1 check caculator
3x-3z=6 -3x – 2z = -11 -------------------------------- Add -5z=-5 z=1
thats gana change my other answers ill have to go back through
y + z = -1 (subtitution z= 1) y+1 =-1 y = -1-1 y =-2
3x + 3y = 3 3x + 3(-2) = 3 3x-6=3 3x=3+6 x=9/3 x=3
i got same for x
good now plug and check
I plug z=1 x=3 y=-2 the answer is correct
i got same those equations take forever!
I'm glad u can solve problem now ,some time u have to use sutittution
i can do the simple ones no problem but when they get complex i tend to get mixed up in my steps
this problem frist step u have to use sutitution
u know now?
yeah i was using the same method just got mixed up in the initial steps for finding z
I tutor my son he like solve by sbutitution instate elemate
cool im doing an electricians math course its been a very long time since ive done systems of equations
ok bye
thanks
np
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